How to return the asynchronous Dart function?
You can get the value like this: SharedPreferences sharedPreferences; Future token() async { sharedPreferences = expect SharedPreferences. get Instance(); back “Lorem ipsum pain”; } token(). then((value) { print(value); });
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What is async called in Dart?
In the example above, calling demo() returns the future. Any function that you want to execute asynchronously must have the asynchronous modifier added. This modifier comes right after the function signature, like so: Dart.
What is asynchronous promise?
If you use the async keyword before a function definition, you can use await inside the function. When it expects a promise, the function stops without blocking until the promise is set. If the promise is fulfilled, you get the value back. If the promise is rejected, the rejected value is cast.
How to return a promise from an async function?
your getData function will return a Promise. Then you can: wait for the function as well to get the result. However, in order to use await, it must be in an async function, so you need to ‘wrap’ this: async function callAsync() { var x = await getData(); console.log(x); } callAsync();
How to return an object from an async method?
GetCurrentPosition currently has an empty return type, so if you want to return a value of a certain type, you need to define the return type. Because it’s also an asynchronous function, the return type for GetCurrentPosition should be a task like this: I tried it but it only returns the task information like asyncState, id, status,Exceptions and many others.
How to return an ajax result using async/await?
Trying to get familiar with async/await, I tried the following code in Chrome: but the result does not contain the result(string); rather it contains a Promise to be expected again. This code gives me the response string: How can I return the actual response string from a function using await?
How to return the result of an asynchronous function?
Let’s say you have this problem: You’re making an asynchronous call, and you need the result of that call to be returned from the original function. but asynchronousFunction() makes some asynchronous call (for example, a fetch() call), and cannot directly return the value of the result.